We answer a question of Bardakov (Kourovka Notebook, Problem 19.8) which asks for the existence of a pair of natural numbers (c, c, m ) with the property that every element in the free group on the two-element set { a, b } can be represented as a concatenation of c , or fewer, m-almost-palindromes in letters a +/- 1, +/- 1 , b +/- 1 . Here, an m-almost-palindrome is a word which can be obtained from a palindrome by changing at most m letters. We show that no such pair (c, c, m ) exists. In fact, we show that the analogous result holds for all non-abelian free groups.
